Optimal. Leaf size=205 \[ \frac{2 \left (21 a^3 A+21 a^2 b B+21 a A b^2+5 b^3 B\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{2 \left (15 a^2 A b+5 a^3 B+9 a b^2 B+3 A b^3\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 b \left (18 a^2 B+21 a A b+5 b^2 B\right ) \sin (c+d x) \sqrt{\cos (c+d x)}}{21 d}+\frac{2 b^2 (11 a B+7 A b) \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{35 d}+\frac{2 b B \sin (c+d x) \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2}{7 d} \]
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Rubi [A] time = 0.477762, antiderivative size = 205, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {2990, 3033, 3023, 2748, 2641, 2639} \[ \frac{2 \left (21 a^3 A+21 a^2 b B+21 a A b^2+5 b^3 B\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{2 \left (15 a^2 A b+5 a^3 B+9 a b^2 B+3 A b^3\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 b \left (18 a^2 B+21 a A b+5 b^2 B\right ) \sin (c+d x) \sqrt{\cos (c+d x)}}{21 d}+\frac{2 b^2 (11 a B+7 A b) \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{35 d}+\frac{2 b B \sin (c+d x) \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2}{7 d} \]
Antiderivative was successfully verified.
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Rule 2990
Rule 3033
Rule 3023
Rule 2748
Rule 2641
Rule 2639
Rubi steps
\begin{align*} \int \frac{(a+b \cos (c+d x))^3 (A+B \cos (c+d x))}{\sqrt{\cos (c+d x)}} \, dx &=\frac{2 b B \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2 \sin (c+d x)}{7 d}+\frac{2}{7} \int \frac{(a+b \cos (c+d x)) \left (\frac{1}{2} a (7 a A+b B)+\frac{1}{2} \left (5 b^2 B+7 a (2 A b+a B)\right ) \cos (c+d x)+\frac{1}{2} b (7 A b+11 a B) \cos ^2(c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 b^2 (7 A b+11 a B) \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2 \sin (c+d x)}{7 d}+\frac{4}{35} \int \frac{\frac{5}{4} a^2 (7 a A+b B)+\frac{7}{4} \left (15 a^2 A b+3 A b^3+5 a^3 B+9 a b^2 B\right ) \cos (c+d x)+\frac{5}{4} b \left (21 a A b+18 a^2 B+5 b^2 B\right ) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 b \left (21 a A b+18 a^2 B+5 b^2 B\right ) \sqrt{\cos (c+d x)} \sin (c+d x)}{21 d}+\frac{2 b^2 (7 A b+11 a B) \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2 \sin (c+d x)}{7 d}+\frac{8}{105} \int \frac{\frac{5}{8} \left (21 a^3 A+21 a A b^2+21 a^2 b B+5 b^3 B\right )+\frac{21}{8} \left (15 a^2 A b+3 A b^3+5 a^3 B+9 a b^2 B\right ) \cos (c+d x)}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 b \left (21 a A b+18 a^2 B+5 b^2 B\right ) \sqrt{\cos (c+d x)} \sin (c+d x)}{21 d}+\frac{2 b^2 (7 A b+11 a B) \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2 \sin (c+d x)}{7 d}+\frac{1}{5} \left (15 a^2 A b+3 A b^3+5 a^3 B+9 a b^2 B\right ) \int \sqrt{\cos (c+d x)} \, dx+\frac{1}{21} \left (21 a^3 A+21 a A b^2+21 a^2 b B+5 b^3 B\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 \left (15 a^2 A b+3 A b^3+5 a^3 B+9 a b^2 B\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 \left (21 a^3 A+21 a A b^2+21 a^2 b B+5 b^3 B\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{2 b \left (21 a A b+18 a^2 B+5 b^2 B\right ) \sqrt{\cos (c+d x)} \sin (c+d x)}{21 d}+\frac{2 b^2 (7 A b+11 a B) \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{35 d}+\frac{2 b B \sqrt{\cos (c+d x)} (a+b \cos (c+d x))^2 \sin (c+d x)}{7 d}\\ \end{align*}
Mathematica [A] time = 1.26794, size = 158, normalized size = 0.77 \[ \frac{10 \left (21 a^3 A+21 a^2 b B+21 a A b^2+5 b^3 B\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )+42 \left (15 a^2 A b+5 a^3 B+9 a b^2 B+3 A b^3\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+b \sin (c+d x) \sqrt{\cos (c+d x)} \left (5 \left (42 a^2 B+42 a A b+3 b^2 B \cos (2 (c+d x))+13 b^2 B\right )+42 b (3 a B+A b) \cos (c+d x)\right )}{105 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 3.418, size = 664, normalized size = 3.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{3}}{\sqrt{\cos \left (d x + c\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{B b^{3} \cos \left (d x + c\right )^{4} + A a^{3} +{\left (3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (B a^{2} b + A a b^{2}\right )} \cos \left (d x + c\right )^{2} +{\left (B a^{3} + 3 \, A a^{2} b\right )} \cos \left (d x + c\right )}{\sqrt{\cos \left (d x + c\right )}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{3}}{\sqrt{\cos \left (d x + c\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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